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((2^(x-1))/(3^(4x+3)))=1
We move all terms to the left:
((2^(x-1))/(3^(4x+3)))-(1)=0
Domain of the equation: (3^(4x+3)))!=0We multiply all the terms by the denominator
x∈R
((2^(x-1))-1*(3^(4x+3)))=0
We calculate terms in parentheses: +((2^(x-1))-1*(3^(4x+3))), so:
(2^(x-1))-1*(3^(4x+3))
We calculate terms in parentheses: +(2^(x-1)), so:
2^(x-1)
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2^(x-1)
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2^(x-1)
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2^(x-1)
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2^(x-1)
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We
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